*/
    int nEq;
    int bInEst = 0;
    int nInMul = 1;
    int nBound = 100;
    int bSort = 0;
    int bLookup = 0;


    /* Determine the values of nEq and nInMul */
    for(nEq=0; nEq<pProbe->nColumn; nEq++){
      WhereTerm *pTerm;           /* A single term of the WHERE clause */
      int j = pProbe->aiColumn[nEq];
      pTerm = findTerm(pWC, iCur, j, notReady, eqTermMask, pIdx);
      if( pTerm==0 ) break;
      wsFlags |= (WHERE_COLUMN_EQ|WHERE_ROWID_EQ);
      if( pTerm->eOperator & WO_IN ){
        Expr *pExpr = pTerm->pExpr;
        wsFlags |= WHERE_COLUMN_IN;
................................................................................
      if( m==0 ){
        wsFlags |= WHERE_IDX_ONLY;
      }else{
        bLookup = 1;
      }
    }

    /**** Begin adding up the cost of using this index (Needs improvements)
    **
    ** Estimate the number of rows of output.  For an IN operator,
    ** do not let the estimate exceed half the rows in the table.
    */
    nRow = (double)(aiRowEst[nEq] * nInMul);
    if( bInEst && nRow*2>aiRowEst[0] ){
      nRow = aiRowEst[0]/2;
      nInMul = (int)(nRow / aiRowEst[nEq]);
................................................................................
    ** doing table lookups.  This reduces the cost by half.  (Not really -
    ** this needs to be fixed.)
    */
    if( pIdx && bLookup==0 ){
      cost /= (double)2;
    }
    /**** Cost of using this index has now been computed ****/

































    WHERETRACE((
      "%s(%s): nEq=%d nInMul=%d nBound=%d bSort=%d bLookup=%d wsFlags=0x%x\n"
      "         notReady=0x%llx nRow=%.2f cost=%.2f used=0x%llx\n",
      pSrc->pTab->zName, (pIdx ? pIdx->zName : "ipk"), 
      nEq, nInMul, nBound, bSort, bLookup, wsFlags, notReady, nRow, cost, used
    ));

    /* If this index is the best we have seen so far, then record this
    ** index and its cost in the pCost structure.
    */
    if( (!pIdx || wsFlags) && cost<pCost->rCost ){


      pCost->rCost = cost;
      pCost->nRow = nRow;
      pCost->used = used;
      pCost->plan.wsFlags = (wsFlags&wsFlagMask);
      pCost->plan.nEq = nEq;
      pCost->plan.u.pIdx = pIdx;
    }
................................................................................
  assert( pCost->plan.u.pIdx==0 || (pCost->plan.wsFlags&WHERE_ROWID_EQ)==0 );
  assert( pSrc->pIndex==0 
       || pCost->plan.u.pIdx==0 
       || pCost->plan.u.pIdx==pSrc->pIndex 
  );

  WHERETRACE(("best index is: %s\n", 

    (pCost->plan.u.pIdx ? pCost->plan.u.pIdx->zName : "ipk")
  ));
  
  bestOrClauseIndex(pParse, pWC, pSrc, notReady, pOrderBy, pCost);
  bestAutomaticIndex(pParse, pWC, pSrc, notReady, pCost);
  pCost->plan.wsFlags |= eqTermMask;
}

................................................................................
#endif
        {
          bestBtreeIndex(pParse, pWC, pTabItem, mask, pOrderBy, &sCost);
        }
        assert( isOptimal || (sCost.used&notReady)==0 );

        if( (sCost.used&notReady)==0
         && (j==iFrom || sCost.rCost<bestPlan.rCost) 

        ){
          bestPlan = sCost;
          bestJ = j;
        }
        if( doNotReorder ) break;
      }
    }

    */
    int nEq;
    int bInEst = 0;
    int nInMul = 1;
    int nBound = 100;
    int bSort = 0;
    int bLookup = 0;
    WhereTerm *pTerm;           /* A single term of the WHERE clause */

    /* Determine the values of nEq and nInMul */
    for(nEq=0; nEq<pProbe->nColumn; nEq++){

      int j = pProbe->aiColumn[nEq];
      pTerm = findTerm(pWC, iCur, j, notReady, eqTermMask, pIdx);
      if( pTerm==0 ) break;
      wsFlags |= (WHERE_COLUMN_EQ|WHERE_ROWID_EQ);
      if( pTerm->eOperator & WO_IN ){
        Expr *pExpr = pTerm->pExpr;
        wsFlags |= WHERE_COLUMN_IN;
................................................................................
      if( m==0 ){
        wsFlags |= WHERE_IDX_ONLY;
      }else{
        bLookup = 1;
      }
    }

    /*

    ** Estimate the number of rows of output.  For an IN operator,
    ** do not let the estimate exceed half the rows in the table.
    */
    nRow = (double)(aiRowEst[nEq] * nInMul);
    if( bInEst && nRow*2>aiRowEst[0] ){
      nRow = aiRowEst[0]/2;
      nInMul = (int)(nRow / aiRowEst[nEq]);
................................................................................
    ** doing table lookups.  This reduces the cost by half.  (Not really -
    ** this needs to be fixed.)
    */
    if( pIdx && bLookup==0 ){
      cost /= (double)2;
    }
    /**** Cost of using this index has now been computed ****/

    /* If there are additional constraints on this table that cannot
    ** be used with the current index, but which might lower the number
    ** of output rows, adjust the nRow value accordingly.  This only 
    ** matters if the current index is the least costly, so do not bother
    ** with this step if we already know this index will not be chosen.
    */
    if( nRow>2 && cost<=pCost->rCost ){
      int k;
      int nSkip = nEq;
      Bitmask thisTab = getMask(pWC->pMaskSet, iCur);
      for(pTerm=pWC->a, k=pWC->nTerm; nRow>2 && k; k--, pTerm++){
        if( pTerm->wtFlags & TERM_VIRTUAL ) continue;
        if( (pTerm->prereqAll & notReady)!=thisTab ) continue;
        if( pTerm->eOperator & (WO_EQ|WO_IN|WO_ISNULL) ){
          if( nSkip ){
            /* Ignore the first nEq equality matches since the index
            ** has already accounted for these */
            nSkip--;
          }else{
            /* Assume each additional equality match reduces the result
            ** set size by a factor of 10 */
            nRow /= 10;
          }
        }else{
          /* Any other expression lowers the output row count by half */
          nRow /= 2;
        }
      }
      if( nRow<2 ) nRow = 2;
    }


    WHERETRACE((
      "%s(%s): nEq=%d nInMul=%d nBound=%d bSort=%d bLookup=%d wsFlags=0x%x\n"
      "         notReady=0x%llx nRow=%.2f cost=%.2f used=0x%llx\n",
      pSrc->pTab->zName, (pIdx ? pIdx->zName : "ipk"), 
      nEq, nInMul, nBound, bSort, bLookup, wsFlags, notReady, nRow, cost, used
    ));

    /* If this index is the best we have seen so far, then record this
    ** index and its cost in the pCost structure.
    */
    if( (!pIdx || wsFlags)
     && (cost<pCost->rCost || (cost==pCost->rCost && nRow<pCost->nRow))
    ){
      pCost->rCost = cost;
      pCost->nRow = nRow;
      pCost->used = used;
      pCost->plan.wsFlags = (wsFlags&wsFlagMask);
      pCost->plan.nEq = nEq;
      pCost->plan.u.pIdx = pIdx;
    }
................................................................................
  assert( pCost->plan.u.pIdx==0 || (pCost->plan.wsFlags&WHERE_ROWID_EQ)==0 );
  assert( pSrc->pIndex==0 
       || pCost->plan.u.pIdx==0 
       || pCost->plan.u.pIdx==pSrc->pIndex 
  );

  WHERETRACE(("best index is: %s\n", 
    ((pCost->plan.wsFlags & WHERE_NOT_FULLSCAN)==0 ? "none" : 
         pCost->plan.u.pIdx ? pCost->plan.u.pIdx->zName : "ipk")
  ));
  
  bestOrClauseIndex(pParse, pWC, pSrc, notReady, pOrderBy, pCost);
  bestAutomaticIndex(pParse, pWC, pSrc, notReady, pCost);
  pCost->plan.wsFlags |= eqTermMask;
}

................................................................................
#endif
        {
          bestBtreeIndex(pParse, pWC, pTabItem, mask, pOrderBy, &sCost);
        }
        assert( isOptimal || (sCost.used&notReady)==0 );

        if( (sCost.used&notReady)==0
         && (j==iFrom || sCost.rCost<bestPlan.rCost
             || (sCost.rCost==bestPlan.rCost && sCost.nRow<bestPlan.nRow))
        ){
          bestPlan = sCost;
          bestJ = j;
        }
        if( doNotReorder ) break;
      }
    }